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Q.For an event A if P(A)=35P(A) = \dfrac{3}{5}, then P(A′)P(A') is equal to :

(a) \dfrac{7}{8}
(b) \dfrac{5}{3}
(c) \dfrac{2}{3}
(d) \dfrac{2}{5}
Jammu Kashmir JkboseJammu and Kashmir Board of School Education (Class 11) 2025MCQ· 1mImportance★★★★★
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Complementary events satisfy P(A)+P(A′)=1P(A) + P(A') = 1, so with P(A)=3/5P(A)=3/5, P(A′)=2/5P(A')=2/5.

For any event AA and its complement A′A' (the event that AA does not occur), the probabilities always satisfy:

P(A)+P(A′)=1.P(A) + P(A') = 1.

Given P(A)=35P(A) = \dfrac{3}{5}: …

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