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Q.Find the mean deviation about the median for the data as under: 13,17,16,14,11,13,10,16,11,18,12,1713, 17, 16, 14, 11, 13, 10, 16, 11, 18, 12, 17.

Jammu Kashmir JkboseJammu and Kashmir Board of School Education (Class 11) 2024Subjective· 2mImportance★★★★★
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For the data 10,11,11,12,13,13,14,16,16,17,17,1810,11,11,12,13,13,14,16,16,17,17,18 (sorted), the median is 13.513.5 and the mean deviation about the median is 73≈2.33\dfrac{7}{3}\approx2.33.

The given data is: 13,17,16,14,11,13,10,16,11,18,12,1713, 17, 16, 14, 11, 13, 10, 16, 11, 18, 12, 17 (n=12n=12 values).

Step 1 — Sort the data:

10,11,11,12,13,13,14,16,16,17,17,1810, 11, 11, 12, 13, 13, 14, 16, 16, 17, 17, 18

Step 2 — Find the median. Since n=12n=12 is even, the median is the average of the 66th and 77th values:

Median=13+142=13.5\text{Median} = \dfrac{13+14}{2} = 13.5

Step 3 — Find ∣xi−Median∣|x_i - \text{Median}| for each value:

| xix_i | ∣xi−13.5∣|x_i-13.5| |

|---|---|

| 10 | 3.5 |

| 11 | 2.5 |

| 11 | 2.5 |

| 12 | 1.5 |

| 13 | 0.5 |

| 13 | 0.5 |

| 14 | 0.5 | …

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