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Q.Evaluate: integral of 1 / sqrt(x - 1) dx.

Jammu Kashmir JkboseJammu and Kashmir Board of School Education (Class 11) 2018Subjective· 2mImportance★★★★★
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Substituting u = x - 1 reduces the integral to the standard form of u^(-1/2), giving 2 sqrt(x-1) + C.

We need to evaluate: Integral of [1 / sqrt(x - 1)] dx

Use the substitution: let u = x - 1. Then du/dx = 1, so du = dx.

Rewriting the integral in terms of u:

Integral of [1/sqrt(u)] du = Integral of u^(-1/2) du

Using the standard power-rule for integration, Integral of u^n du = u^(n+1)/(n+1) + C (for n not equal to -1), with n = -1/2:

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