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Q.Integration of the definite integral of cos x dx from -pi/2 to +pi/2 is:

(a) Zero
(b) 1
(c) 2
(d) 3
Jammu Kashmir JkboseJammu and Kashmir Board of School Education (Class 11) 2018MCQ· 1mImportance★★★★★
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Integrating cos x gives sin x; evaluating between the limits -pi/2 and +pi/2 gives sin(pi/2) - sin(-pi/2) = 1 - (-1) = 2.

The integral to evaluate is:

Integral from -pi/2 to +pi/2 of cos x dx

The antiderivative of cos x is sin x, since d/dx (sin x) = cos x. So:

Integral from -pi/2 to +pi/2 of cos x dx = [sin x] evaluated from -pi/2 to +pi/2

= sin(pi/2) - sin(-pi/2)

sin(pi/2) = 1, and sin(-pi/2) = -sin(pi/2) = -1 (since sine is an odd function).

= 1 - (-1) = 1 + 1 = 2

…

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