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Q.A particle moving in a circular path of radius r with velocity v. Then centripetal acceleration of the particle is

(1) v^2 r
(2) r / v^2
(3) v / r
(4) v^2 / r
Jharkhand JacJAC Intermediate Board (1st Year) 2019MCQ· 2mImportance★★★★★
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Centripetal acceleration a_c = v²/r, directed toward the centre of the circular path.

For a particle moving in a circle of radius r with speed v, even though the SPEED may be constant, the VELOCITY direction is continuously changing, producing an acceleration directed toward the centre. This can be derived from the rate of change of the velocity vector (using small-angle geometry of the velocity triangle) and gives the standard result:

a_c = v²/r (equivalently a_c = ω²r, since v = ωr). …

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