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Question of 135

Q.Draw the structures of the following compounds:

a) 1-ethoxy propane
b) 4-methyl pent-3-en-2-one
c) 3-bromo-4-phenyl pentanoic acid
d) o-Toluidine
e) m-kresol
Jharkhand JacJAC Intermediate Board 2025Subjective· 5mImportance★★★★★
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Each structure is built directly from its IUPAC name by locating the parent chain/ring, numbering it, and placing every named substituent at its stated position.

a) 1-Ethoxypropane: a propyl group joined via oxygen to an ethyl group.

CH3-CH2-CH2-O-CH2-CH3\text{CH}_3\text{-CH}_2\text{-CH}_2\text{-O-CH}_2\text{-CH}_3

b) 4-Methylpent-3-en-2-one: a 5-carbon chain, ketone at C2, double bond C3-C4, methyl branch at C4.

CH3-CO-CH=C(CH3)-CH3(i.e. CH3COCH=C(CH3)2)\text{CH}_3\text{-CO-CH=C(CH}_3\text{)-CH}_3 \quad (\text{i.e. CH}_3\text{COCH=C(CH}_3\text{)}_2)

c) 3-Bromo-4-phenylpentanoic acid: a 5-carbon acid chain (C1 = COOH), Br at C3, phenyl at C4.

HOOC-CH2-CHBr-CH(C6H5)-CH3\text{HOOC-CH}_2\text{-CHBr-CH(C}_6\text{H}_5\text{)-CH}_3

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