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Q.Write IUPAC name of CH3.C(C2H5)2.CH2Br.

Jharkhand JacJAC Intermediate Board 2018Subjective· 1mImportance★★★★★
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IUPAC naming always starts by finding the LONGEST continuous carbon chain in the structure; here that chain runs through both ethyl branches (5 carbons, a pentane), leaving -CH3 and -CH2Br as two substituents on its middle carbon.

STRUCTURE: CH3-C(C2H5)2-CH2Br is a central carbon bonded to four groups: a -CH3, two -C2H5 (ethyl) groups, and a -CH2Br group. Total: 7 carbon atoms, 1 bromine.

STEP 1 - Find the longest chain: Tracing a path through the two ethyl branches AND the central carbon gives a continuous run of 5 carbons: CH3-CH2-C(...)-CH2-CH3. This is longer than the alternative path through the central carbon plus the -CH2Br arm (only 4 carbons). By the rule 'always select the longest possible continuous chain first,' the parent chain is this 5-carbon PENTANE, with the original central carbon becoming C-3 (the middle carbon, by symmetry).

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