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Q.

Find the median of the following data.

Wages (in ₹)60-7050-6040-5030-4020-30
No. of Workers7211165
Karnataka PUCKarnataka 1st PUC Commerce Board 2020Subjective· 6mImportance★★★★★
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Reorder classes ascending, N = 50, N/2 = 25 falls in class 50-60; Median = 50 + ((25 − 22)/21) × 10 = ₹51.43 (approx).

This 6-mark numerical from Karnataka 1st PUC Economics (Measures of Central Tendency) gives the classes in descending order, so they must first be arranged in ascending order.

Step 1 — Arrange classes in ascending order and find cumulative frequency (cf):

Wages (₹)No. of Workers (f)Cumulative Frequency (cf)
20-3055
30-40611
40-501122
50-602143
60-70750
TotalN = 50

Step 2 — Find N/2: N/2 = 50/2 = 25.

Step 3 — Locate the median class: Find the class whose cumulative frequency is just greater than or equal to 25. The cf values are 5, 11, 22, 43, 50 — the first cf ≥ 25 is 43, which belongs to the class 50-60. So the median class is 50-60.

Step 4 — Identify the values for the formula:

  • L (lower limit of median class) = 50 …

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