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Q.10 mL of liquid A is mixed with 10 mL of liquid B, the volume of the resultant solution is 19.9 mL. What type of deviation is expected from Raoult's law?

Karnataka PUCKarnataka II PUC Board 2020Subjective· 1mImportance★★★★★
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Volume contracts on mixing (20→19.920 \to 19.9 mL), showing stronger A–B attractions than A–A/B–B, so it is a negative deviation from Raoult's law.

Concept. Raoult's law describes an ideal solution where A–A, B–B and A–B intermolecular forces are equal, so there is no volume change and no enthalpy change on mixing. Deviations arise when A–B forces differ from A–A/B–B forces.

Why this conclusion. If A–B attractions are stronger than the average of A–A and B–B, molecules pack more tightly, the volume decreases (ΔVmix<0\Delta V_{mix} < 0), heat is released (ΔHmix<0\Delta H_{mix} < 0), and vapour pressure falls below the Raoult's-law prediction — this is negative deviation.

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