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Q.A random variable X has the following probability distribution:
X: 0 1 2 3 4
P(X): 0.1 k 2k 2k k
Determine:

(i) k
(ii) P(X ≥ 2).
Karnataka PUCKarnataka II PUC Board 2018Subjective· 2mImportance★★★★★
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k=0.15k=0.15 and P(X≥2)=0.75P(X\ge2)=0.75.

Concept. For a probability distribution, ∑P(X)=1\sum P(X)=1, and each P(X)≥0P(X)\ge0.

Step-by-step. (i) Sum the probabilities: …

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