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Q.Show that the relation R defined in the set A of all triangles as R = {(T_1, T_2) : T_1 is similar to T_2} is an equivalence relation.

Karnataka PUCKarnataka II PUC Board 2020Subjective· 3mImportance★★★★★
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Similarity is reflexive, symmetric and transitive, so RR is an equivalence relation.

Concept. A relation RR on a set AA is an equivalence relation if it is (i) reflexive, (ii) symmetric and (iii) transitive. Here AA is the set of all triangles and R={(T1,T2):T1 is similar to T2}R=\{(T_1,T_2):T_1\text{ is similar to }T_2\}.

Proof.

Reflexive: Every triangle is similar to itself (equal corresponding angles, proportional sides in ratio 1:11:1). So (T,T)∈R(T,T)\in R for all T∈AT\in A. Hence RR is reflexive.

Symmetric: If T1T_1 is similar to T2T_2, then their corresponding angles are equal and sides proportional; the same holds when the two triangles are interchanged, so T2T_2 is similar to T1T_1. Thus (T1,T2)∈R⇒(T2,T1)∈R(T_1,T_2)\in R\Rightarrow(T_2,T_1)\in R, so RR is symmetric.

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