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Q.

Draw a less than and more than ogive for the following frequency distribution and find out the median graphically :

MarksNo. of Students
0 – 105
10 – 206
20 – 3030
30 – 4014
40 – 505
Kerala DhseKerala DHSE Plus One Commerce Board 2026Subjective· 5mImportance★★★★★
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Plot the less-than cf (5, 11, 41, 55, 60) and more-than cf (60, 55, 49, 19, 5) as two ogives; their point of intersection gives the median ≈ 26.33 marks (confirmed by the median formula).

This question is from the Kerala Plus One (DHSE) Statistics for Economics chapter 'Presentation of Data' (ogives). Total frequency N = 5 + 6 + 30 + 14 + 5 = 60, so N/2 = 30.

Step 1 — Cumulative frequencies:

MarksfLess-than cf (plot at upper limit)More-than cf (plot at lower limit)
0 – 105less than 10 → 5more than 0 → 60
10 – 206less than 20 → 11more than 10 → 55
20 – 3030less than 30 → 41more than 20 → 49
30 – 4014less than 40 → 55more than 30 → 19
40 – 505less than 50 → 60more than 40 → 5

Step 2 — Draw the ogives: On graph paper, plot the less than ogive using the points (10,5), (20,11), (30,41), (40,55), (50,60) and join them by a smooth rising curve. Plot the more than ogive using (0,60), (10,55), (20,49), (30,19), (40,5) and join by a smooth falling curve.

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