Skip to content
Question of 109

Q.Identify the positions of Al (z=13) and S (z=16) in the periodic table with the help of their electronic configurations. Predict the formula of the compound formed between them.

Kerala DhseKerala DHSE Plus One Board 2019Subjective· 2mImportance★★★★★
0% · 0/109 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Both Al and S are in Period 3; their outer-shell electron configurations place Al in Group 13 (3 valence electrons, forms Al³⁺) and S in Group 16 (6 valence electrons, forms S²⁻), so the ionic compound formed by charge balance is Al2S3.

Electronic configurations:

  • Al (Z = 13): 1s² 2s² 2p⁶ 3s² 3p¹ (or [Ne] 3s² 3p¹)
  • S (Z = 16): 1s² 2s² 2p⁶ 3s² 3p⁴ (or [Ne] 3s² 3p⁴)

Locating them in the periodic table:

  • Both elements have their outermost (valence) electrons in the n = 3 shell, so both are in Period 3.
  • Aluminium has 3 electrons in its outermost shell (3s²3p¹, total 3 valence electrons) → it belongs to Group 13 (the boron family), and typically loses 3 electrons to form the Al³⁺ cation (achieving the stable [Ne] configuration).
  • Sulfur has 6 electrons in its outermost shell (3s²3p⁴, total 6 valence electrons) → it belongs to Group 16 (the oxygen family/chalcogens), and typically gains 2 electrons to form the S²⁻ anion (achieving the stable [Ar] configuration). …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.