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Q.(i) Which of the following compound does not show cis-trans isomerism ?
(A) CHCl = CHCl (B) CH3CH = CHCH3
(C) CH3CCl = CClCH3 (D) (CH3)2C = CHC2H5

(1)
(ii) Draw the Newman projections of eclipsed and staggered conformations of ethane. (2)
Kerala DhseKerala DHSE Plus One Board 2022Subjective· 3mImportance★★★★★
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Figure — Part (ii) explicitly asks to 'Draw the Newman projections of eclipsed and staggered conformations of ethane',
Figure — Part (ii) explicitly asks to 'Draw the Newman projections of eclipsed and staggered conformations of ethane',

Cis-trans isomerism needs two DIFFERENT groups on each doubly-bonded carbon; (D) fails this because one carbon bears two identical methyl groups. Newman projections show the relative rotation (dihedral angle) between front and back C-H bonds around the C-C axis.

(i) For cis-trans (geometric) isomerism to be possible around a C=C double bond, each of the two doubly-bonded carbons must carry two different groups/atoms.

  • (A) CHCl=CHCl: each carbon has H and Cl (different) → shows cis-trans isomerism.
  • (B) CH3CH=CHCH3: each carbon has H and CH3 (different) → shows cis-trans isomerism.
  • (C) CH3CCl=CClCH3: each carbon has CH3 and Cl (different) → shows cis-trans isomerism.
  • (D) (CH3)2C=CHC2H5: one of the doubly-bonded carbons carries two identical CH3 groups — since the two substituents on that carbon are the same, this molecule cannot show cis-trans isomerism.

Answer: (D)

(ii) Newman projections of ethane (viewed along the C–C bond):

In a Newman projection, the front carbon is shown as a dot with three bonds radiating out at 120° to each other (to its 3 H atoms), and the back carbon is shown as a circle with three bonds also at 120° to each other (to its 3 H atoms), the two sets differing by their relative rotation (dihedral angle) about the central C–C axis.

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