Q.What is meant by disproportionation reactions ? Give one example.
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Disproportionation Reactions: The Self-Oxidation-Reduction
Imagine you have a group of friends who are all equally tall. Now imagine that, for no external reason, some of them suddenly grow taller while others shrink shorter — all starting from the same height. That sounds strange, right? But that's exactly what happens in a disproportionation reaction: the same element, in the same starting oxidation state, simultaneously gets oxidised (loses electrons) and reduced (gains electrons).
In other words, one part of the substance acts as the oxidising agent, and another part acts as the reducing agent — on itself.
The Intuition First
Think of a chemical element like chlorine. In its elemental form (Cl2), each chlorine atom has an oxidation state of 0. Now, if you put chlorine gas into water, something odd happens:
- Some chlorine atoms gain an electron (reduction) and become Cl− (oxidation state -1).
- Other chlorine atoms lose an electron (oxidation) and become ClO− (oxidation state +1).
The same starting material (Cl2) produces two different products — one more reduced, one more oxidised. That's disproportionation.
The word "disproportionation" literally means "not in proportion" — the original uniform state splits into two different states.
The Precise Definition
A disproportionation reaction is a redox reaction in which a single substance (element or compound) in an intermediate oxidation state simultaneously undergoes both oxidation and reduction, producing two different products — one with a higher oxidation state and one with a lower oxidation state.
The key conditions are:
- One reactant — the same species is both oxidised and reduced.
- Intermediate oxidation state — the starting element must be able to go both higher and lower.
- Two products — one more oxidised, one more reduced.
The Classic Example: Chlorine in Water
Cl2+H2O→HCl+HOCl
Let's track the oxidation states:
| Species | Oxidation state of Cl |
|---|---|
| Cl2 | 0 |
| HCl | -1 (reduced) |
| HOCl | +1 (oxidised) |
The chlorine in Cl2 (oxidation state 0) goes to -1 (gain of electron = reduction) and to +1 (loss of electron = oxidation). The same element, same starting state, two different directions.
A common mistake is to think that because Cl2 is a single molecule, it must be either oxidised or reduced. But each chlorine atom in Cl2 can behave differently — one gets oxidised, the other gets reduced. The reaction as a whole is a disproportionation.
How to Spot a Disproportionation Reaction
Look for these three clues:
- One reactant, two products — especially if the reactant contains an element that can exist in multiple oxidation states.
- The same element appears in two different oxidation states in the products — one higher, one lower than the starting state.
- No external oxidising or reducing agent — the substance does it to itself.
More Examples
Hydrogen peroxide decomposition:
2H2O2→2H2O+O2
Oxygen in H2O2 has oxidation state -1. In H2O, oxygen is -2 (reduced). In O2, oxygen is 0 (oxidised). The -1 state is intermediate between -2 and 0.
Copper(I) chloride in aqueous solution:
2CuCl→Cu+CuCl2
Copper in CuCl is +1. It goes to 0 (reduced) and +2 (oxidised).
Ammonium nitrite decomposition:
NH4NO2→N2+2H2O
Nitrogen in NH4+ is -3, in NO2− is +3. Both go to 0 in N2 — this is actually the reverse (comproportionation), but it shows how the same element can meet in the middle.
The Opposite: Comproportionation …
A disproportionation reaction is one in which the same element in a single oxidation state is simultaneously oxidised and reduced. …
Disproportionation = same element in one oxidation state is both oxidised and reduced; e.g. 2H2O2 -> 2H2O + O2 (O goes -1 -> -2 and -1 -> 0).
In a disproportionation reaction, an element present in one intermediate oxidation state changes into two different oxidation states - one higher (oxidation) and one lower (reduction) - in the same reaction.
Example: 2H2O2 -> 2H2O + O2. …
- CBSE 2025Set ANNUAL1 markMCQQ.Which of the following species do not show disproportionation reaction?(a) ClO-(b) ClO2-(c) ClO3-(d) ClO4-
›Reveal solutionSolution
In ClO4−, chlorine is already at its highest possible oxidation state (+7), so it has nowhere to go but down — it cannot simultaneously be oxidised, which disproportionation requires.
Disproportionation is a redox reaction in which the SAME element, in a single intermediate oxidation state, is simultaneously oxidised (goes to a higher state) and reduced (goes to a lower state) in two of its atoms/ions.
Oxidation states of Cl in each species:
- ClO−: Cl is +1 — can go up (to +3,+5,+7) or down (to −1) ⇒ can disproportionate.
- ClO2−: Cl is +3 — can go up or down ⇒ can disproportionate.
- ClO3−: Cl is +5 — can go up (to +7) or down ⇒ can disproportionate. …
- CBSE 2024Set ANNUAL1 markMCQQ.Oxidation number of sodium in sodium chloride is(a) A) +2(b) B) +1(c) C) 0(d) D) -1
›Reveal solutionSolution
[!TLDR]
B) +1
Why
In NaCl, sodium exists as Na+, giving it an oxidatio …
- CBSE 2022Set ANNUAL1 markQ.What is disproportionation reaction?
›Reveal solutionSolution
Disproportionation is a special redox reaction where one species acts as both the oxidising agent and the reducing agent, because the same element in it is simultaneously oxidised and reduced.
Normally, in a redox reaction, one substance is oxidised and a DIFFERENT substance is reduced. In disproportionation, a single species containing an element in an intermediate oxidation state splits so that part of it is oxidised to a higher state and part is reduced to a lower state.
Example: 2H2O2 → 2H2O + O2
In H2O2, oxygen is in the -1 oxidation state. In the products, oxygen in H2O is -2 (reduced) and oxygen in O2 is 0 (oxidised). So H2O2 disproportionates.
…
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