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Q.a) If 32n+2−8n−93^{2n+2} - 8n - 9 is divisible by kk for all n∈Nn \in N is true, then which one of the following is a value of kk?

(1)
i) 88 ii) 66 iii) 33 iv) 1212
b) Prove by using the principle of Mathematical Induction P(n)=1+3+32+…+3n−1=3n−12P(n) = 1 + 3 + 3^2 + \ldots + 3^{n-1} = \dfrac{3^n - 1}{2} is true for all n∈Nn \in N. (3)
Kerala DhseKerala DHSE Plus One Board 2018Subjective· 4mImportance★★★★★
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Testing small n shows 3^(2n+2) − 8n − 9 is a multiple of 8; the sum identity is proved by the standard induction steps (base + inductive).

a) Put n = 1: 3⁴ − 8 − 9 = 81 − 17 = 64. Put n = 2: 3⁶ − 16 − 9 = 729 − 25 = 704. Both are divisible by 8 (64 = 8·8, 704 = 8·88), while 6, 3, 12 do not divide 64. So k = 8 → option (i).

b) Let P(n): 1 + 3 + 3² + … + 3^(n−1) = (3ⁿ − 1)/2.

Base step (n = 1): LHS = 1; RHS = (3¹ − 1)/2 = 2/2 = 1. True.

Inductive step: assume P(k) true, i.e. 1 + 3 + … + 3^(k−1) = (3ᵏ − 1)/2.

Add the next term 3ᵏ to both sides: …

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