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Q.(i) Let R be a relation on the set Z, set of integers defined by R = {(a, b) : 2 divides (a − b)}. Choose the right answer:
(A) (2, 4) ∈ R (B) (3, 8) ∈ R (C) (7, 6) ∈ R (D) (8, 7) ∈ R

(1)
(ii) Check the above relation R is an equivalence relation. (3)
Kerala DhseKerala DHSE Plus Two Board 2023Subjective· 4mImportance★★★★★
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Only (2,4) satisfies '2 divides a−b'; and R is reflexive, symmetric and transitive, so it's an equivalence relation.

R={(a,b):2 divides (a−b)}R = \{(a,b): 2 \text{ divides } (a-b)\} on Z\mathbb{Z}.

  1. Checking the options (A) (2,4)(2,4): 2−4=−22-4=-2, and 2∣−22 \mid -2 — true. (B) (3,8)(3,8): 3−8=−53-8=-5, and 2∤−52 \nmid -5 — false. (C) (7,6)(7,6): 7−6=17-6=1, and 2∤12 \nmid 1 — false. (D) (8,7)(8,7): 8−7=18-7=1, and 2∤12 \nmid 1 — false. So the answer is (A) (2,4)∈R(2,4) \in R.
  2. Is R an equivalence relation? Reflexive: For any a∈Za \in \mathbb{Z}, a−a=0a-a=0, and 2∣02\mid 0. So (a,a)∈R(a,a)\in R for all aa — R is reflexive. Symmetric: If (a,b)∈R(a,b)\in R, then a−b=2ka-b=2k for some integer kk. Then b−a=−2k=2(−k)b-a = -2k = 2(-k), which is also divisible by 2, so (b,a)∈R(b,a)\in R — R is symmetric. …

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