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Q.Write the IUPAC names of the following compounds:

(i) H2C=CH-CH=CH2
(ii) CH3-CH2-CH=CH-CH3
(iii) CH3-CH(OH)-CH(Br)-C(=O)-CH3
(iv) CH3-CH2-CH(CH3)-CH(C2H5)-CH2-CH3 OR Draw structural formulas of the following compounds from their IUPAC names:
(i) 1,3,5-Trinitrobenzene
(ii) Methoxypropane
(iii) 1,3,5-Hexatriene
(iv) Propane-1,2,3-triol
Madhya Pradesh MpbseMP Board Higher Secondary (Class 11) 2024Subjective· 4mImportance★★★★★
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Each structure is named by finding the longest chain containing the senior (highest-priority) functional group, numbering to give that group the lowest locant, and listing substituent prefixes alphabetically.

  1. H2C=CH-CH=CH2: a 4-carbon chain with double bonds at both the 1,2 and 3,4 positions. IUPAC name: Buta-1,3-diene.
  2. CH3-CH2-CH=CH-CH3: a 5-carbon chain with the double bond between C2 and C3 (numbering from the end giving the lower locant). IUPAC name: Pent-2-ene.
  3. CH3-CH(OH)-CH(Br)-C(=O)-CH3: a 5-carbon chain bearing -OH, -Br, and a ketone (C=O). Functional group seniority for the principal suffix: ketone (-one) outranks both -ol (alcohol) and halo (always a prefix only). Numbering to give the ketone carbon the lowest possible locant: numbering from the methyl ketone end gives C1=CH3(terminal), C2=C(=O), C3=CH(Br), C4=CH(OH), C5=CH3 -- so the ketone is at C2, Br at C3, OH at C4. Substituent prefixes in alphabetical order: bromo before hydroxy. IUPAC name: 3-Bromo-4-hydroxypentan-2-one.
  4. CH3-CH2-CH(CH3)-CH(C2H5)-CH2-CH3: the longest chain is 6 carbons (hexane), with a methyl branch and an ethyl branch on adjacent carbons. Numbering from either end gives the same locant set {3,4} for the two substituents; the tie is broken by giving the lower locant to the substituent cited first alphabetically (ethyl before methyl), so ethyl = C3, methyl = C4. IUPAC name: 3-Ethyl-4-methylhexane. …

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