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Q.Find the equation of the line which makes intercepts −3-3 and 22 on the x-axis and y-axis respectively. OR Find the distance between the parallel lines 15x+8y−34=015x + 8y - 34 = 0 and 15x+8y+31=015x + 8y + 31 = 0.

Madhya Pradesh MpbseMP Board Higher Secondary (Class 11) 2024Subjective· 2mImportance★★★★★
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Using the intercept form xa+yb=1\frac{x}{a}+\frac{y}{b}=1 with a=−3,b=2a=-3, b=2 gives 2x−3y+6=02x-3y+6=0.

Step 1. The intercept form of a line with x-intercept aa and y-intercept bb is xa+yb=1\dfrac{x}{a} + \dfrac{y}{b} = 1.

Step 2. Here a=−3a = -3, b=2b = 2: x−3+y2=1\dfrac{x}{-3} + \dfrac{y}{2} = 1.

Step 3. Multiply through by 66 (LCM of 3, 2): −2x+3y=6-2x + 3y = 6, i.e. 2x−3y+6=02x - 3y + 6 = 0.

Step 4. Check: at y=0y=0, x=−3x=-3 ✓; at x=0x=0, y=2y=2 ✓.

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