Q.What is Self inductance? Derive an expression for the self inductance of a solenoid. Also write the factors affecting it. OR What is a Transformer? Describe its principle and the different types of energy losses in it.
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Start your 14-day free trial to unlock the full solution →Self-inductance quantifies a coil's opposition to changing current, and for a solenoid it depends on turns density, area, and core material; a transformer transfers power via mutual induction, with real transformers losing some energy to resistive and magnetic-core effects.
Self-inductance: Self-inductance is the property of a coil (or circuit) by virtue of which it opposes any change in the current flowing through it, by inducing an emf in itself. It is defined through the relation (flux linkage proportional to current) or equivalently by the induced emf , where is the coefficient of self-inductance, measured in henry (H).
Derivation for a long solenoid: Consider a solenoid of length , cross-sectional area , with total turns (so turns per unit length), carrying current . The magnetic field inside a long solenoid is (assumed uniform):
The magnetic flux linked with each turn is , and the total flux linkage with all turns is:
Comparing with :
If the solenoid has a magnetic core of relative permeability , this becomes .
Factors affecting self-inductance: (1) number of turns (or turns density ) — ; (2) cross-sectional area of the solenoid — ; (3) length of the solenoid; (4) permeability of the core material — inserting a ferromagnetic (high-) core greatly increases .
OR — Transformer: A transformer is a static device used to change (step up or step down) an alternating voltage, consisting of two coils — a primary and a secondary — wound on a common laminated iron core. Its principle is mutual induction: an alternating current in the primary coil produces a continuously changing magnetic flux in the core, which links the secondary coil and induces an alternating emf in it, with the voltage ratio equal to the turns ratio: .
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