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Q.Following table gives the marks obtained by 100 students in statistics subject. Marks : 20 10 50 40 30
No. of students : 10 5 25 20 40 Find the average and median marks of students. Or Compute mean deviation from mean of the following data : Marks : 0–10 10–20 20–30 30–40 40–50
No. of students : 5 10 20 5 10

Manipur CohsemCOHSEM Manipur Higher Secondary 1st Year (Commerce) 2020Subjective· 8mImportance★★★★★est
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Sorting the discrete series by marks and using the direct method: Mean = Σfx/Σf = 3500/100 = 35; Median (the value where cumulative frequency first reaches N/2 = 50) = 30.

Step 1 — Arrange the series by marks (ascending) with cumulative frequency (cf):

Marks (x)No. of students (f)fxcf
105505
201020015
3040120055
402080075
50251250100
TotalΣf = N = 100Σfx = 3500

Average (Arithmetic Mean):

Mean (x̄) = Σfx / Σf = 3500 / 100 = 35 marks

Median (discrete series): Locate N/2 = 100/2 = 50th item using the cumulative frequency column. The cf first equals/exceeds 50 at marks = 30 (cf = 55, having jumped from cf = 15 at marks = 20). So the median lies at marks = 30.

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