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Q.A question paper contains 12 questions, divided into three parts. Part A contains 6 questions, while part B and part C contains 3 questions each. A candidate is required to attempt 6 questions selecting atleast two from part A and atleast one from each of part B and C. In how many ways can the candidate select 6 questions?

Manipur CohsemCouncil of Higher Secondary Education, Manipur (Higher Secondary 1st Year) 2026Subjective· 6mImportance★★★★★
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Summing the combinations over every valid (a,b,c) split with a≥2, b≥1, c≥1, a+b+c=6 gives 720 total ways.

Part A has 6 questions, Part B has 3, Part C has 3. The candidate picks 6 total, with at least 2 from A, at least 1 from B, and at least 1 from C.

Let (a,b,c) = number chosen from A, B, C respectively, with a+b+c=6a+b+c=6, a≥2a\ge2, b≥1b\ge1, c≥1c\ge1, and each capped by its part's size (a≤6a\le6, b≤3b\le3, c≤3c\le3).

The valid splits are: (2,1,3), (2,2,2), (2,3,1), (3,1,2), (3,2,1), (4,1,1).

For each split, the number of ways is (6a)(3b)(3c)\binom{6}{a}\binom{3}{b}\binom{3}{c}:

  • (2,1,3): (62)(31)(33)=15×3×1=45\binom62\binom31\binom33 = 15\times3\times1=45
  • (2,2,2): (62)(32)(32)=15×3×3=135\binom62\binom32\binom32 = 15\times3\times3=135
  • (2,3,1): (62)(33)(31)=15×1×3=45\binom62\binom33\binom31 = 15\times1\times3=45
  • (3,1,2): (63)(31)(32)=20×3×3=180\binom63\binom31\binom32 = 20\times3\times3=180 …

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