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Q.The volume of the spherical balloon being inflated changes at a constant rate. If initially its radius is 33 units and after 33 seconds it is 66 units, find the radius of the balloon after tt seconds.

Manipur CohsemCOHSEM Manipur Higher Secondary Board 2026Subjective· 3mImportance★★★★★
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V=kt+CV=kt+C with V=43πr3V=\tfrac43\pi r^3; the data r(0)=3, r(3)=6r(0)=3,\ r(3)=6 give r3=63t+27r^3=63t+27.

Step 1: Volume V=43πr3V=\dfrac{4}{3}\pi r^{3}. Constant rate: dVdt=k\dfrac{dV}{dt}=k, so V=kt+CV=kt+C.

Step 2: At t=0t=0, r=3r=3: V=43π(27)=36π=C.V=\dfrac43\pi(27)=36\pi=C.

Step 3: At t=3t=3, r=6r=6: V=43π(216)=288π=3k+36π⇒3k=252π⇒k=84π.V=\dfrac43\pi(216)=288\pi=3k+36\pi\Rightarrow 3k=252\pi\Rightarrow k=84\pi.

Step 4: So 43πr3=84πt+36π⇒r3=34(84t+36)=63t+27.\dfrac43\pi r^{3}=84\pi t+36\pi\Rightarrow r^{3}=\dfrac34(84t+36)=63t+27.

Hence r=(63t+27)1/3r=(63t+27)^{1/3}.

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