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Q.How does the L-C circuit produce oscillation? Explain.

Manipur CohsemCOHSEM Manipur Higher Secondary Board 2018Subjective· 3mImportance★★★★★
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LC oscillation = energy repeatedly converting between the capacitor's electric field and the inductor's magnetic field, an electrical analogue of SHM.

Consider a capacitor CC, initially charged to charge Q0Q_0, connected across an inductor LL (an ideal LC circuit, no resistance):

  1. Initial state: all the energy is stored in the capacitor's electric field, UE=Q022CU_E = \dfrac{Q_0^2}{2C}; no current flows yet, so UB=0U_B = 0.
  2. Discharge begins: the capacitor starts to discharge through the inductor. As current II builds up, the inductor develops a magnetic field, storing energy UB=12LI2U_B = \tfrac12 LI^2; simultaneously, QQ on the capacitor decreases, so UEU_E decreases. By energy conservation (no resistance to dissipate energy), the total energy remains constant: Q22C+12LI2=Q022C=constant\frac{Q^2}{2C} + \frac12 LI^2 = \frac{Q_0^2}{2C} = \text{constant}
  3. Capacitor fully discharged: at this instant Q=0Q=0, so all the energy is now in the inductor's magnetic field, UB=12LI02U_B = \tfrac12 LI_0^2, and current is maximum.
  4. Current continues, recharges C (opposite polarity): the inductor opposes any change in current (self-induction), so current keeps flowing, recharging the capacitor with the opposite polarity. Energy flows back from the magnetic field into the capacitor's electric field.
  5. Cycle reverses and repeats: once the capacitor is fully charged (opposite polarity) current becomes zero again, and the whole process reverses, repeating indefinitely.

Applying Kirchhoff's voltage law to this loop, LdIdt+QC=0L\dfrac{dI}{dt} + \dfrac{Q}{C}=0, and using I=−dQ/dtI=-dQ/dt, gives …

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