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Q.Assume that light of wavelength 0.5 μm0.5\,\mu m is coming from a star. What is the limit of angular resolution in radians of a telescope whose objective has a radius 122 cm.?

Manipur CohsemCOHSEM Manipur Higher Secondary Board 2020Subjective· 1mImportance★★★★★
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Δθ=1.22λ/D≈2.5×10−7 rad\Delta\theta = 1.22\lambda/D \approx 2.5\times10^{-7}\,rad, using aperture diameter D=2×(radius)D = 2\times(\text{radius}).

The limit of angular resolution (minimum resolvable angle) of a telescope, set by diffraction at its circular objective, is

Δθ=1.22 λD\Delta\theta = \frac{1.22\,\lambda}{D}

where DD is the diameter of the objective aperture and λ\lambda is the wavelength of light.

Given λ=0.5 μm=5×10−7 m\lambda = 0.5\,\mu m = 5\times10^{-7}\,m and the objective's radius =122 cm=1.22 m= 122\,cm = 1.22\,m, the aperture diameter is

D=2×1.22 m=2.44 mD = 2 \times 1.22\,m = 2.44\,m

Δθ=1.22×5×10−72.44=6.1×10−72.44=2.5×10−7 rad\Delta\theta = \frac{1.22 \times 5\times10^{-7}}{2.44} = \frac{6.1\times10^{-7}}{2.44} = 2.5\times10^{-7}\,rad

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