Question of 112
Q.(a) On the basis of molecular Hydride classify the following compound as electron deficient, electron precise and electron rich hydrides. [2]
B2H6, CH4, H2O and NH3.
(b) What are amphoteric oxide? Give example. [1]
OR
(c) Starting from Borax, how Boric acid is prepared? Give balance chemical equation. [2]
(d) What happen when Al is treated with dilute NaOH solution? [1]
Meghalaya MboseMBOSE Meghalaya 11th Board 2022Subjective· 3mImportance★★★★★
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Start your 14-day free trial to unlock the full solution →Hydrides are classed as electron-deficient (fewer than 8 electrons around the central atom), electron-precise (exactly 8), or electron-rich (more than 8, with lone pairs) based on the octet at the central atom; amphoteric oxides react with both acids and bases.
(a) Classification of hydrides:
- B2H6 (diborane): Boron has only 3 valence electrons and does not have enough electrons to complete an octet through normal 2-electron bonds (it uses unusual 3-centre-2-electron 'banana' bonds to bridge boron and hydrogen). This makes B2H6 an electron-deficient hydride.
- CH4 (methane): Carbon forms exactly 4 single bonds to 4 hydrogen atoms, giving it exactly a complete octet with no lone pairs left over. This makes CH4 an electron-precise hydride.
- H2O (water): Oxygen forms 2 bonds to hydrogen and retains 2 lone pairs — more electron pairs around the central atom than are needed just for bonding. This makes H2O an electron-rich hydride. …
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