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Q.(a) Calculate the volume occupied by 8.8 g of CO2 at 31.1 degC and 1 bar pressure. R = 0.083 bar L K^-1 mol^-1. [2]

(b) Write the formula of van der Waal's equation of state. [1]
Meghalaya MboseMBOSE Meghalaya 11th Board 2019Subjective· 3mImportance★★★★★
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(a) 8.8 g CO2 occupies about 5.05 L at 31.1°C and 1 bar. (b) The van der Waals equation is (P + an²/V²)(V - nb) = nRT.

(a) Volume of 8.8 g CO2 at 31.1°C and 1 bar:

Moles of CO2: molar mass of CO2 = 12 + 2(16) = 44 g/mol

n=8.8 g44 g/mol=0.2 moln = \frac{8.8\ \text{g}}{44\ \text{g/mol}} = 0.2\ \text{mol}

Temperature in Kelvin: T = 31.1 + 273 = 304.1 K (commonly taken as 304 K)

Using the ideal gas equation, PV = nRT, with R = 0.083 bar L K^-1 mol^-1 and P = 1 bar:

V=nRTP=(0.2)(0.083)(304.1)1V = \frac{nRT}{P} = \frac{(0.2)(0.083)(304.1)}{1}

V=0.2×0.083×304.11≈5.05 LV = \frac{0.2 \times 0.083 \times 304.1}{1} \approx 5.05\ \text{L}

So the volume occupied is approximately 5.05 L.

(b) Van der Waals equation of state:

Real gases deviate from ideal behaviour because their molecules have a finite (non-zero) volume and experience intermolecular attractive forces, both of which the ideal gas equation ignores. Van der Waals corrected the ideal gas equation PV = nRT by introducing two correction terms: …

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