Q.(a) Calculate the volume occupied by 8.8 g of CO2 at 31.1 degC and 1 bar pressure. R = 0.083 bar L K^-1 mol^-1. [2]
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Start your 14-day free trial to unlock the full solution →(a) 8.8 g CO2 occupies about 5.05 L at 31.1°C and 1 bar. (b) The van der Waals equation is (P + an²/V²)(V - nb) = nRT.
(a) Volume of 8.8 g CO2 at 31.1°C and 1 bar:
Moles of CO2: molar mass of CO2 = 12 + 2(16) = 44 g/mol
Temperature in Kelvin: T = 31.1 + 273 = 304.1 K (commonly taken as 304 K)
Using the ideal gas equation, PV = nRT, with R = 0.083 bar L K^-1 mol^-1 and P = 1 bar:
So the volume occupied is approximately 5.05 L.
(b) Van der Waals equation of state:
Real gases deviate from ideal behaviour because their molecules have a finite (non-zero) volume and experience intermolecular attractive forces, both of which the ideal gas equation ignores. Van der Waals corrected the ideal gas equation PV = nRT by introducing two correction terms: …
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