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Q.The relation ff is defined by
[!FORMULA] f(x)={x2,0≤x≤33x,3≤x≤10f(x)=\begin{cases} x^2, & 0 \le x \le 3 \\ 3x, & 3 \le x \le 10 \end{cases}
The relation gg is defined by
[!FORMULA] g(x)={x2,0≤x≤23x,2≤x≤10g(x)=\begin{cases} x^2, & 0 \le x \le 2 \\ 3x, & 2 \le x \le 10 \end{cases}
Show that ff is a function and gg is not a function.

Meghalaya MboseMBOSE Meghalaya 11th Board 2023Subjective· 4mImportance★★★★★
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ff is a function because its two pieces agree at the shared boundary point; gg is not, because its pieces disagree there.

A rule is a function only if every input value is assigned exactly ONE output.

For ff: the pieces x2x^2 (on [0,3][0,3]) and 3x3x (on [3,10][3,10]) overlap only at x=3x=3.

At x=3x=3: first piece gives 32=93^2=9; second piece gives 3(3)=93(3)=9. Both agree — f(3)=9f(3)=9 unambiguously. Every other xx is covered by exactly one piece. So ff is a well-defined function.

For gg: the pieces x2x^2 (on [0,2][0,2]) and 3x3x (on [2,10][2,10]) overlap only at x=2x=2. …

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