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Q.State whether the following sets are equal or not: I={x:x2−5x+7=0, x∈R}I = \{x : x^2 - 5x + 7 = 0,\ x \in R\} and J=ϕJ = \phi

Meghalaya MboseMBOSE Meghalaya 11th Board 2019Subjective· 4mImportance★★★★★
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II has no real elements, so I=∅=JI=\varnothing=J; the two sets are equal.

Given I={x:x2−5x+7=0, x∈R}I=\{x: x^2-5x+7=0,\ x\in\mathbb{R}\} and J=∅J=\varnothing.

Find the discriminant of x2−5x+7=0x^2-5x+7=0:

D=b2−4ac=(−5)2−4(1)(7)=25−28=−3D = b^2-4ac = (-5)^2-4(1)(7) = 25-28 = -3

Since D<0D<0, the equation has no real roots - only complex (non-real) roots exist.

Since we require x∈Rx\in\mathbb{R}, no real number satisfies the equation, so:

I=∅I = \varnothing

Given J=∅J=\varnothing (the empty set) as well.

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