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Q.If the three points A(a,0)A(a,0), B(0,b)B(0,b) and P(x,y)P(x,y) are collinear, using slopes, prove that xa+yb=1\dfrac{x}{a}+\dfrac{y}{b}=1.

Meghalaya MboseMBOSE Meghalaya 11th Board 2018Subjective· 2mImportance★★★★★
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Equating slope of APAP with slope of ABAB and simplifying gives the intercept form xa+yb=1\dfrac{x}{a}+\dfrac{y}{b}=1.

Since A(a,0)A(a,0), B(0,b)B(0,b), P(x,y)P(x,y) are collinear, the slope of line APAP must equal the slope of line ABAB.

Slope of ABAB:

mAB=b−00−a=−bam_{AB}=\frac{b-0}{0-a}=-\frac{b}{a}

Slope of APAP:

mAP=y−0x−a=yx−am_{AP}=\frac{y-0}{x-a}=\frac{y}{x-a}

Setting mAP=mABm_{AP}=m_{AB}:

yx−a=−ba\frac{y}{x-a}=-\frac{b}{a}

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