Q.(a) Write the structures of the products of the following reactions:
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Start your 14-day free trial to unlock the full solution →Soda-lime decarboxylation of sodium acetate gives methane; HCN addition to acetaldehyde gives a cyanohydrin. (Alternative: carboxylic-acid dimerisation via H-bonding explains their unusually high boiling points, and inductive electron withdrawal explains relative acid strengths.)
(a)(i) Soda-lime decarboxylation:
Heating the sodium salt of a carboxylic acid with soda lime (NaOH + CaO) removes the carboxyl group as , leaving the alkane with one less carbon:
Product: methane, .
(a)(ii) Cyanohydrin formation:
Aldehydes react with hydrogen cyanide (nucleophilic addition of to the electrophilic carbonyl carbon, followed by protonation) to give a cyanohydrin:
Product: acetaldehyde cyanohydrin (2-hydroxypropanenitrile), .
Alternative (Or):
(b) Why carboxylic acids boil higher than aldehydes/ketones/alcohols of similar mass:
Carboxylic acid molecules associate strongly in the liquid/vapour state, forming a cyclic dimer held together by two intermolecular hydrogen bonds simultaneously (each ):
Breaking these two hydrogen bonds to vaporise the acid requires considerably more energy than vaporising an alcohol (which forms only single, not doubled, H-bonds) or an aldehyde/ketone (which cannot hydrogen-bond with itself at all, having no O–H). This extra energy requirement raises the boiling point of carboxylic acids well above that of alcohols, aldehydes or ketones of comparable molecular mass.
(c) vs :
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