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Q.Draw the structure of the major monohalo product: cyclohexanol (cyclohexane ring with an −OH-OH substituent) +SOCl2→?+ SOCl_2 \rightarrow ?

Meghalaya MboseMBOSE Meghalaya Intermediate Board 2025Subjective· 1mImportance★★★★★
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SOCl2_2 replaces the –OH of cyclohexanol by –Cl, giving chlorocyclohexane; SO2_2 and HCl are the by-products.

Cyclohexanol reacts with thionyl chloride (best carried out in the presence of pyridine, which absorbs the HCl formed) by the following overall equation:

C6H11OH+SOCl2→pyridineC6H11Cl+SO2↑+HCl↑C_6H_{11}OH + SOCl_2 \xrightarrow{\text{pyridine}} C_6H_{11}Cl + SO_2\uparrow + HCl\uparrow

Mechanism (briefly): the oxygen of the alcohol attacks the electrophilic sulfur of SOCl2_2, displacing Cl−^- and forming an alkyl chlorosulfite ester, C6H11−O−S(=O)−ClC_6H_{11}-O-S(=O)-Cl, with loss of HCl. This chlorosulfite is a good leaving group; the chloride ion (released in the same step, or delivered by pyridinium chloride) then displaces it, either from the front side (SNii, retention of configuration, in the absence of a base) or the back side (SN2, inversion, when pyridine is present to remove HCl and free Cl−^-), giving the monochloro produc …

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