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Q.Using differential, find the approximate value of 1273\sqrt[3]{127}.

Meghalaya MboseMBOSE Meghalaya Intermediate Board 2019Subjective· 4mImportance★★★★★
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Take f(x)=x1/3f(x)=x^{1/3} near the nearby perfect cube x=125x=125 (whose cube root is exactly 55), and use the differential dy≈f′(x) dxdy\approx f'(x)\,dx to approximate f(127)f(127).

Step 1 — Choose f(x)f(x) and the base point.

Let f(x)=x1/3f(x)=x^{1/3}. Choose x=125x=125 (since 125=53125=5^3 is the nearest perfect cube to 127127, so f(125)=5f(125)=5 exactly) and let dx=Δx=127−125=2dx=\Delta x=127-125=2.

Step 2 — Differentiate.

f′(x)=13x−2/3=13x2/3.f'(x)=\frac{1}{3}x^{-2/3}=\frac{1}{3x^{2/3}}.

At x=125x=125: 1252/3=(1251/3)2=52=25125^{2/3}=(125^{1/3})^2=5^2=25, so

f′(125)=13(25)=175.f'(125)=\frac{1}{3(25)}=\frac{1}{75}.

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