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Q.There are three coins. One is a two-headed coin (having head on both faces), another is a biased coin that comes up heads 75% of the time and third is an unbiased coin. One of the three coins is chosen at random and tossed, it shows heads. What is the probability that it is the two-headed coin?

Meghalaya MboseMBOSE Meghalaya Intermediate Board 2026Subjective· 5mImportance★★★★★
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Use Bayes' theorem: find the overall probability of getting heads (weighted over the three equally-likely coin choices), then find what fraction of that total probability comes from the two-headed coin.

Let A1A_1 = two-headed coin chosen, A2A_2 = biased coin chosen, A3A_3 = unbiased coin chosen. Since one of three coins is picked at random:

P(A1)=P(A2)=P(A3)=13P(A_1)=P(A_2)=P(A_3) = \frac13

Let HH = event of getting heads. The conditional probabilities of heads given each coin:

P(H∣A1)=1(two heads, always shows heads)P(H\mid A_1)=1 \quad(\text{two heads, always shows heads})

P(H∣A2)=75100=34(biased coin)P(H\mid A_2)=\frac{75}{100}=\frac34 \quad(\text{biased coin})

P(H∣A3)=12(unbiased/fair coin)P(H\mid A_3)=\frac12 \quad(\text{unbiased/fair coin})

Step 1: Find P(H)P(H) using the law of total probability.

P(H)=P(A1)P(H∣A1)+P(A2)P(H∣A2)+P(A3)P(H∣A3)P(H) = P(A_1)P(H\mid A_1)+P(A_2)P(H\mid A_2)+P(A_3)P(H\mid A_3) …

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