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Q.A conductor of resistance RR is stretched to two times its initial length, keeping the volume constant. What will be its new resistance?

(a) 2R2R
(b) R/2R/2
(c) 4R4R
(d) RR
Meghalaya MboseMBOSE Meghalaya Intermediate Board 2023MCQ· 1mImportance★★★★★
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Stretching a wire to twice its length at constant volume halves its cross-sectional area, so the resistance increases by a factor of 4.

Solution:

Resistance of a conductor: R=ρlAR = \dfrac{\rho l}{A}, where ρ\rho is resistivity (a material constant, unchanged by stretching), ll is length, AA is cross-sectional area.

Volume is constant: V=lA=l′A′V = lA = l'A'

Given l′=2ll' = 2l, so: …

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