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Q.From the given circuit, find the value of current flowing through the 2 Ω2\ \Omega resistor. Assume that D1D_1 and D2D_2 are two ideal diodes.

three parallel branches with diode D1 and 3 ohm, a 2 ohm with 20 V, and diode D2 with 4 ohm — Class 12 Physics semiconductor electronics question
Figure
Meghalaya MboseMBOSE Meghalaya Intermediate Board 2020Subjective· 2mImportance★★★★★
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Only one of the two anti-parallel diodes can be forward biased for a given battery polarity; the branch with the reverse-biased diode simply carries no current, leaving a single series loop to solve with Ohm's law.

Step 1 — Determine which diode conducts

D1D_1 and D2D_2 point in opposite directions between the same two nodes. For the polarity set by the 20 V battery in the middle branch, only one of them is forward biased; the other is reverse biased and (being ideal) behaves as an open circuit, so no current flows through the branch containing the reverse-biased diode (the 4 Ω branch with D2D_2, in the standard reading of this figure).

Step 2 — Reduce to a single series loop

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