The line (x−3)/2 = (y−4)/−3 = (z−1)/5 crosses the xy plane at – (a) (13/5, 23/5, 0) (b) (13/5, 0, 23/5) (c) (0, 13/5, 23/5) (d) (13/5, 23/5, 33/5)

> > [!TLDR] > Write the line in parametric form and set $z=0$ (the condition for the xy-plane) to solve for the parameter. > …

The line (x−3)/2 = (y−4)/−3 = (z−1)/5 crosses the

Question of 64

Q. The line (x-3)/2 = (y-4)/-3 = (z-1)/5 crosses the xy plane at -

(a) (13/5, 23/5, 0)

(b) (13/5, 0, 23/5)

(d) (13/5, 23/5, 33/5)

Mizoram MbseMizoram Board of School Education HSSLC 2023MCQ· 1mImportance★★★★★est

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