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Q.The kinetic energy of an electron has been found to be 5.76×10−155.76\times10^{-15}J. Calculate the wavelength associated with the electrons.

Nagaland NbseNagaland Board of School Education (Class XI) 2024Subjective· 3mImportance★★★★★
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Get the electron's momentum from its kinetic energy, then use the de Broglie relation to find the associated wavelength.

Kinetic energy KE=p22m⇒p=2mKEKE = \dfrac{p^2}{2m} \Rightarrow p = \sqrt{2mKE}, with me=9.11×10−31m_e = 9.11\times10^{-31} kg and KE=5.76×10−15KE = 5.76\times10^{-15} J.

p=2×9.11×10−31×5.76×10−15=1.049×10−44≈1.024×10−22 kg m/sp = \sqrt{2 \times 9.11\times10^{-31} \times 5.76\times10^{-15}} = \sqrt{1.049\times10^{-44}} \approx 1.024\times10^{-22}\ \text{kg m/s}

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