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Q.How high must a body be lifted to gain an amount of potential energy equal to kinetic energy it has, when moving at a speed of 20 ms−120\,ms^{-1}. The value of acceleration due to gravity at a place is 9.8 ms−29.8\,ms^{-2}. OR Calculate the work done needed to accelerate a car of mass 1400 kg from rest to 90 km/hr within a distance of 40 m.

Nagaland NbseNagaland Board of School Education (Class XI) 2024Subjective· 2mImportance★★★★★
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Setting gravitational PE equal to the given KE, h=v2/(2g)≈20.4 mh = v^2/(2g) \approx 20.4\,m.

The kinetic energy of the body moving at speed v=20 ms−1v = 20\,ms^{-1} is KE=12mv2KE = \dfrac{1}{2}mv^2. We want the height hh to which it must be lifted so that its gravitational potential energy PE=mghPE = mgh equals this KE:

mgh=12mv2  ⟹  h=v22gmgh = \dfrac{1}{2}mv^2 \implies h = \dfrac{v^2}{2g}

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