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Q.a) Define molecularity and order of reaction. Derive an expression for the rate constant of a zero-order reaction. (1.5+1.5+2) b) The half-life period of a first order reaction is 30 minutes. How much time is required for 75% completion of the reaction? (log 2 = 0.301) (2)

Odisha ChseOdisha CHSE +2 Science Board Exam 2020Subjective· 7mImportance★★★★★
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Molecularity is a theoretical count of colliding species in an elementary step; order is the experimentally observed sum of concentration exponents in the rate law. For a zero-order reaction, k = ([R]0-[R])/t. Using t1/2 = 30 min for a first-order reaction, 75% completion takes 60 minutes (exactly two half-lives).

a) Molecularity of a reaction: the number of reacting species (atoms, ions, or molecules) that must collide simultaneously in order to bring about a chemical reaction in a single elementary step. It is a theoretical concept, determined from the balanced equation of the elementary reaction/mechanism step, and it is always a whole number (1, 2, or rarely 3) - it can never be zero or fractional.

Order of a reaction: the sum of the powers (exponents) to which the concentration terms are raised in the experimentally determined rate law of the reaction. Unlike molecularity, order is an experimental quantity, and it can be zero, a fraction, or a whole number, and it is defined for the overall (often multi-step) reaction, not necessarily a single elementary step.

Derivation of the zero-order rate constant expression: For a zero-order reaction, R -> P, the rate is independent of the concentration of the reactant:

Rate = -d[R]/dt = k [R]^0 = k

Separating variables: -d[R] = k dt

Integrating both sides between the limits [R] = [R]0 at t = 0 and [R] = [R] at time t:

−∫[R]0[R]d[R]=k∫0tdt-\int_{[R]_0}^{[R]} d[R] = k\int_0^t dt

[R]0−[R]=kt[R]_0 - [R] = kt

k=[R]0−[R]tk = \dfrac{[R]_0 - [R]}{t}

b) Given: t(1/2) for the first-order reaction = 30 minutes.

First-order rate constant: k=0.693t1/2=0.69330=0.0231 min−1k = \dfrac{0.693}{t_{1/2}} = \dfrac{0.693}{30} = 0.0231\ \text{min}^{-1}

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