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Q.There are three bags B1B_1, B2B_2 and B3B_3 having respectively 4 white, 5 black; 3 white, 6 black and 6 white, 3 black balls. A bag is chosen at random and a ball is drawn from it. Find the probability that the ball is black.

Odisha ChseOdisha CHSE +2 Science Board Exam 2025Subjective· 5mImportance★★★★★
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Use the law of total probability: average the "black" probability from each bag, weighted by 13\frac13 each.

Each bag (B1,B2,B3B_1,B_2,B_3) has 9 balls total and is chosen with probability 13\dfrac13.

  • P(black∣B1)=59P(\text{black}\mid B_1) = \dfrac59 (4 white, 5 black)
  • P(black∣B2)=69P(\text{black}\mid B_2) = \dfrac69 (3 white, 6 black)
  • P(black∣B3)=39P(\text{black}\mid B_3) = \dfrac39 (6 white, 3 black)

Law of total probability: …

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