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Q.If 2a⃗+3b⃗−5c⃗=0⃗2\vec{a}+3\vec{b}-5\vec{c}=\vec{0}, then write the ratio in which c⃗\vec{c} divides AB‾\overline{AB}, where the position vectors of AA and BB are respectively a⃗\vec{a} and b⃗\vec{b}.

(a) 3 : 2 internally
(b) 3 : 2 externally
(c) 2 : 3 internally
(d) 2 : 3 externally
Odisha ChseOdisha CHSE +2 Science Board Exam 2026MCQ· 1mImportance★★★★★
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Concept understanding — Section Formula

Section Formula (Vector Form)

Given two points, where is the point that divides the segment joining them in a chosen ratio? The section formula answers this with position vectors, generalising the midpoint to any ratio.

Setup

Let PP and QQ have position vectors a⃗\vec{a} and b⃗\vec{b} (measured from the origin OO). We want the position vector r⃗\vec{r} of the point RR that divides PQPQ in the ratio m:nm:n, i.e. PR:RQ=m:nPR:RQ=m:n.

Internal division

When RR lies between PP and QQ:

r⃗=m b⃗+n a⃗m+n\vec{r}=\frac{m\,\vec{b}+n\,\vec{a}}{m+n}

Notice the cross-pairing: the far endpoint QQ (position b⃗\vec{b}) is weighted by mm, and the near endpoint PP (position a⃗\vec{a}) by nn. The result is a weighted average of the endpoints, so RR sits closer to whichever endpoint carries the larger opposite weight.

Midpoint as a special case

Put m=nm=n (ratio 1:11:1):

r⃗=a⃗+b⃗2,\vec{r}=\frac{\vec{a}+\vec{b}}{2},

the familiar midpoint formula. So the section formula is just a generalised midpoint.

External division

When RR lies on the line PQPQ but outside the segment (say beyond QQ), the denominator changes sign:

r⃗=m b⃗−n a⃗m−n\vec{r}=\frac{m\,\vec{b}-n\,\vec{a}}{m-n}

Important

For external division the denominator is m−nm-n. If m=nm=n it becomes zero — there is no finite point dividing a segment externally in an equal ratio (the point runs off to infinity).

Why it matters …

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