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Q.∫ (from π/6 to π/3) √(cos x) / (√(sin x) + √(cos x)) dx is equal to:

(a) π/4
(b) π/6
(c) π/12
(d) π/2
Punjab PsebPSEB Punjab Class 12 Board 2026MCQ· 1mImportance★★★★★
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Concept understanding — King Property of Definite Integrals

The King Property of Definite Integrals

Walk a path from aa to bb measuring something at each step; now walk it backwards from bb to aa. The King Property says the total is unchanged — provided you also reverse how you measure. It is one of the most useful shortcuts for definite integrals.

∫abf(x) dx=∫abf(a+b−x) dx\int_{a}^{b} f(x) \, dx = \int_{a}^{b} f(a + b - x) \, dx

The limits stay aa to bb; only the argument changes, x→a+b−xx \to a+b-x.

Where it comes from

Substitute t=a+b−xt = a + b - x, so dx=−dtdx = -dt; when x=ax=a, t=bt=b and when x=bx=b, t=at=a:

∫abf(x) dx=∫baf(a+b−t) (−dt)=∫abf(a+b−t) dt.\int_{a}^{b} f(x)\,dx = \int_{b}^{a} f(a+b-t)\,(-dt) = \int_{a}^{b} f(a+b-t)\,dt.

Renaming tt back to xx gives the result. So it is not a trick — just substitution.

Why it helps

Adding the original integral to its "mirror" often collapses the integrand. For instance, with I=∫0π/2sin⁡xsin⁡x+cos⁡x dxI = \int_{0}^{\pi/2} \frac{\sin x}{\sin x + \cos x}\,dx, the property replaces sin⁡x\sin x by cos⁡x\cos x (since sin⁡(π2−x)=cos⁡x\sin(\tfrac{\pi}{2}-x)=\cos x). Adding the two forms:

2I=∫0π/2sin⁡x+cos⁡xsin⁡x+cos⁡x dx=π2,I=π4.2I = \int_{0}^{\pi/2} \frac{\sin x + \cos x}{\sin x + \cos x}\,dx = \frac{\pi}{2}, \qquad I = \frac{\pi}{4}.

Tip

Reach for it when the integrand has sin⁡x,cos⁡x,tan⁡x\sin x,\cos x,\tan x over [0,π/2][0,\pi/2] or [0,π][0,\pi] and f(a+b−x)f(a+b-x) simplifies. If the swapped form is no easier, it will not help.

Watch out

The limits do not change — only the function's argument does. …

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