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Q.Clearly explain the difference between beats and interference.

Rajasthan RbseRajasthan Board Senior Secondary Part-I Examination 2024Subjective· 2mImportance★★★★★
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Concept understanding — Beats

The Intuition: When Two Almost-Identical Notes Clash

Imagine you're tuning a guitar. You pluck the string you want to tune, and simultaneously strike the reference note from a tuning fork. If the two notes are exactly the same pitch, you hear a single, steady tone. But if they are almost the same — say one is 440 Hz and the other is 442 Hz — something strange happens. The sound doesn't stay steady. Instead, it swells in loudness, fades away, swells again, fades again, in a slow, throbbing rhythm. That rhythmic pulsing is what we call beats.

Why does this happen? Because the two waves, travelling together, sometimes add up constructively (making a loud sound) and sometimes cancel each other out (making a near-silence). They are constantly shifting in and out of phase.

The Precise Physics: Superposition of Two Slightly Different Frequencies

Let two waves of equal amplitude AA but slightly different angular frequencies ω1\omega_1 and ω2\omega_2 arrive at your ear. Their displacements at a point can be written as:

y1=Asin⁡(ω1t)y_1 = A \sin(\omega_1 t)

y2=Asin⁡(ω2t)y_2 = A \sin(\omega_2 t)

By the principle of superposition, the resultant displacement is:

y=y1+y2=A[sin⁡(ω1t)+sin⁡(ω2t)]y = y_1 + y_2 = A[\sin(\omega_1 t) + \sin(\omega_2 t)]

Using the sum-to-product identity:

sin⁡P+sin⁡Q=2sin⁡(P+Q2)cos⁡(P−Q2)\sin P + \sin Q = 2 \sin\left(\frac{P+Q}{2}\right) \cos\left(\frac{P-Q}{2}\right)

we get:

y=2Acos⁡(ω1−ω22t)sin⁡(ω1+ω22t)y = 2A \cos\left(\frac{\omega_1 - \omega_2}{2} t\right) \sin\left(\frac{\omega_1 + \omega_2}{2} t\right)

This is the key result. The resultant wave has two parts:

  • A fast oscillation at the average frequency ω1+ω22\frac{\omega_1 + \omega_2}{2} (which is nearly the same as the original frequencies). This is what your ear hears as the pitch.
  • A slowly varying amplitude given by 2Acos⁡(ω1−ω22t)2A \cos\left(\frac{\omega_1 - \omega_2}{2} t\right). This envelope modulates the loudness.

fbeat=∣f1−f2∣f_{\text{beat}} = |f_1 - f_2|

The beat frequency is the absolute difference of the two original frequencies. Your ear perceives one loud-soft cycle for every complete cycle of the cosine envelope. Since the cosine goes through a full cycle when its argument changes by 2π2\pi, the time period of one beat is:

Tbeat=2π∣ω1−ω2∣/2=2π∣ω1−ω2∣T_{\text{beat}} = \frac{2\pi}{|\omega_1 - \omega_2|/2} = \frac{2\pi}{|\omega_1 - \omega_2|}

And since f=ω/2πf = \omega/2\pi, the beat frequency in hertz is simply:

fbeat=∣f1−f2∣f_{\text{beat}} = |f_1 - f_2|

What You Actually Hear

Your ear does not follow the rapid (ω1+ω2)/2(\omega_1 + \omega_2)/2 oscillations individually — that's just the pitch you perceive. What you notice is the envelope: the amplitude rises and falls at the beat frequency. So with 440 Hz and 442 Hz, you hear a note of roughly 441 Hz that grows louder and softer 2 times every second. …

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