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Q.Write general oxidation state of Lanthanoids.
Rajasthan RbseRajasthan Board Senior Secondary Examination 2018Subjective· 1mImportance★★★★★
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Start your 14-day free trial to unlock the full solution →Lanthanoids characteristically show the +3 oxidation state, arising from loss of the two 6s electrons and one 5d/4f electron.
The lanthanoids (Ce to Lu, following La) have the general electronic configuration [Xe] 4f^(1-14) 5d^(0-1) 6s^2. They predominantly lose the two 6s electrons and one 4f (or 5d) electron to attain the stable +3 oxidation state, which is common to all of them. A few lanthanoids also show +2 or +4 states when it leads to an especially stable f^0, f^7 or f^14 configuration (e.g. Ce^4+ …
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