Q.The total revenue in rupees received from the sale of x units of a product is given by R(x)=13x2+26x+15. Find the marginal revenue when x=7.
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Marginal Revenue: The Revenue from One More Unit
Imagine you run a small stall selling lemonade. You sell 10 glasses at ₹10 each, so total revenue is ₹100. Now you wonder: If I sell one more glass, how much extra money will I actually bring in? That extra money — the change in total revenue from the 11th glass — is marginal revenue.
The Core Intuition
Marginal revenue (MR) answers a practical question: "What happens to total revenue when I increase sales by exactly one unit?"
It is not simply the price of that extra unit. Selling one more might force you to lower the price on all units — especially if you have some market power (like a monopoly or a price-setting firm). In perfect competition, where you're a price-taker, MR equals the market price; but in most real-world scenarios, MR is less than the price.
Think of MR as the slope of the total revenue curve. If total revenue is R(q), then MR=dqdR.
The Precise Definition
Marginal Revenue is the rate at which total revenue changes as the quantity sold changes. For a firm selling q units with total revenue R(q):
MR(q)=dqdR
If the demand curve is p(q) (price as a function of quantity), then R(q)=p(q)×q, and by the product rule:
MR(q)=dqd[p(q)⋅q]=p(q)+q⋅dqdp
This says marginal revenue equals the price of the current unit plus the effect that selling one more has on the price of all previous units (since dp/dq is usually negative — to sell more, you lower the price).
MR=p+q⋅dqdp
A Concrete Example
Suppose a monopolist faces demand p=100−2q (price drops ₹2 per extra unit sold), so total revenue is R(q)=q(100−2q)=100q−2q2.
The instantaneous marginal revenue is the derivative:
MR(q)=R′(q)=100−4q
At q=10: MR(10)=100−40=60. Checking with the product-rule formula: p(10)=100−20=80, and dp/dq=−2, so MR=80+10×(−2)=60 — the two methods agree.
Compare this to the discrete one-unit change: at q=10, R=80×10=800; at q=11, p=78 and R=78×11=858, so the actual revenue gained from the 11th unit is 858−800=58.
58 (the real jump from 10 to 11 units) and 60 (the instantaneous derivative at exactly q=10) are close but not identical. The derivative gives the instantaneous slope of the revenue curve at q=10; the discrete difference is the average slope over the step from q=10 to q=11, which also picks up a little of the curve's downward curvature over that step. For a smoothly varying revenue function, the two are always close but only exactly equal when R(q) is linear. …
Marginal revenue is the derivative of the revenue function, so differentiating R(x) and evaluating it …
Marginal revenue is R′(x); differentiate R(x) and evaluate at x=7.
R(x)=13x2+26x+15⇒R′(x)=26x+26.
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- CBSE 2026Set ANNUAL1 markQ.The total revenue in rupees received from the sale of x units of a product is given by R(x)=13x2+26x+15. Find the marginal revenue when x=7.
›Reveal solutionSolution
Marginal revenue is R′(x); differentiate R(x) and evaluate at x=7.
R(x)=13x2+26x+15⇒R′(x)=26x+26.
…
- CBSE 2026Set ANNUAL1 markQ.The total revenue in Rupees received from the sale of x units of a product is given by R(x)=13x2+26x+15. Find the marginal revenue when x=7.
›Reveal solutionSolution
R′(x)=26x+26; at x=7, R′(7)=208.
Marginal revenue is the rate of change of revenue:
R′(x)=dxd(13x2+26x+15)=26x+26.
…
- CBSE 2025Set ANNUAL1 markQ.The total revenue in Rupees received from the sale of x units of a product is given by R(x)=2x2+25x. Then marginal revenue = _____ when x=10.
›Reveal solutionSolution
Marginal revenue is the derivative of the revenue function, R′(x).
R(x)=2x2+25x⇒R′(x)=4x+25
…
- CBSE 2023Set ANNUAL1 markQ.The total revenue in Rupees received from the sale of x units of a product is given by R(x)=3x2+36x+5. Find the marginal revenue when x=15.
›Reveal solutionSolution
Marginal revenue is the derivative of the total revenue function.
Given R(x)=3x2+36x+5.
Marginal revenue MR=dxdR=6x+36.
…
- CBSE 2023Set A1 markQ.The total revenue in Rupees received from the sale of x units of a product is given by R(x)=3x2+36x+5. Find the marginal revenue when x=15.
›Reveal solutionSolution
Marginal revenue is R′(x); differentiating R(x)=3x2+36x+5 gives R′(x)=6x+36, which is 126 at x=15.
…
- CBSE 2023Set ANNUAL1 markQ.The total revenue in Rupees received from the sale of x units of a product is given by R(x)=13x2+26x+15. Find the marginal revenue, when x=7.
›Reveal solutionSolution
Marginal revenue is the derivative of the revenue function, R′(x), evaluated at the given output.
R(x)=13x2+26x+15
R′(x)=26x+26
…
- CBSE 2020Set HE8231 markQ.Give the answer in one word/sentence: The total revenue in Rupees received from the sale of x units of a product is given by R(x)=3x2+36x+5. Write the marginal revenue, when x=15.
›Reveal solutionSolution
Marginal revenue at x=15 is Rs. 126.
Marginal revenue is the derivative of total revenue: MR=dxdR.
R(x)=3x2+36x+5 ⇒ dxdR=6x+36.
At x=15: …
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