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Q.If a=2i−3j+5ka = 2i - 3j + 5k, b=−i+4j+2kb = -i + 4j + 2k, then find a×ba \times b.

Telangana TsbieTelangana Board of Intermediate Education (Intermediate 1st Year) 2022Subjective· 2mImportance★★★★★
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Expand the cross product as a 3×33\times 3 determinant.

Given a⃗=2i^−3j^+5k^\vec a = 2\hat i-3\hat j+5\hat k, b⃗=−i^+4j^+2k^\vec b = -\hat i+4\hat j+2\hat k.

a⃗×b⃗=∣i^j^k^2−35−142∣\vec a\times\vec b = \begin{vmatrix}\hat i & \hat j & \hat k\\ 2 & -3 & 5\\ -1 & 4 & 2\end{vmatrix}

i^\hat i: (−3)(2)−(5)(4)=−6−20=−26(-3)(2)-(5)(4) = -6-20=-26

j^\hat j: −[(2)(2)−(5)(−1)]=−[4+5]=−9-[(2)(2)-(5)(-1)] = -[4+5]=-9 …

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