Q.A solution of glucose in water is labeled as 10% w/w. What would be the molarity of the solution?
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Start your 14-day free trial to unlock the full solution →10% w/w glucose means 10 g in 100 g solution; that is 0.0556 mol in 0.1 L (density approximately 1 g/mL), giving a molarity of about 0.556 M.
'10% w/w' means 10 g of glucose is present in 100 g of solution.
Step 1 - Moles of glucose: Molar mass of glucose (C6H12O6) = 6(12) + 12(1) + 6(16) = 72 + 12 + 96 = 180 g/mol.
Moles of glucose = mass / molar mass = 10 / 180 = 0.0556 mol.
Step 2 - Volume of solution: Taking the density of the (dilute) solution as approximately 1 g/mL,
Volume = mass / density = 100 g / (1 g/mL) = 100 mL = 0.1 L.
Step 3 - Molarity: Molarity = moles of solute / volume of solution in litres.
Molarity = 0.0556 / 0.1 = 0.556 mol/L.
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