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Q.Derive Bragg's equation.

Telangana TsbieTelangana Board of Intermediate Education 2020Subjective· 4mImportance★★★★★
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Concept understanding — X-Ray Diffraction

What is X-Ray Diffraction?

Imagine you're standing at the edge of a perfectly still pond and drop a pebble. Ripples spread outward in circles. Now drop two pebbles a short distance apart. The ripples from each source cross each other. Where a crest meets a crest, the wave gets taller; where a crest meets a trough, they cancel out. That interference pattern — the places where the water is calm and where it's rough — tells you exactly where the two pebbles fell.

X-ray diffraction is the same idea, but with atoms instead of pebbles and X-rays instead of water waves.

When a beam of X-rays hits a crystal, each atom in the crystal scatters the X-rays in all directions — like each atom becomes a tiny pebble dropped into the pond. But a crystal has billions of atoms arranged in neat, repeating planes. The scattered waves from all those atoms interfere with each other. At most angles, they cancel out completely. But at a few very specific angles, the waves from every atom in a plane add up constructively — crest on crest — and produce a strong reflected beam.

Those special angles are the ones that satisfy Bragg's law.

nλ=2dsin⁡θn\lambda = 2d\sin\theta

Here λ\lambda is the wavelength of the X-rays, dd is the distance between adjacent atomic planes, θ\theta is the angle between the incoming X-ray and the plane (not the normal), and nn is a positive integer (1, 2, 3, …) called the order of reflection.

The Geometry Behind the Law

Think of two parallel atomic planes separated by distance dd. An X-ray beam hits the top plane at an angle θ\theta and scatters off an atom there. Another X-ray, parallel to the first, travels a little further down to the next plane and scatters off an atom directly below.

The second ray has to travel an extra distance — down to the lower plane and back up. That extra path length is exactly 2dsin⁡θ2d\sin\theta.

For the two scattered rays to be in phase (crest on crest), this extra distance must equal a whole number of wavelengths: nλn\lambda. If it's anything else, the waves partially or completely cancel.

Watch out

The angle θ\theta in Bragg's law is measured from the plane, not from the normal. This is the opposite of the usual convention in optics (Snell's law, reflection). Many students lose marks by using the wrong angle. Always draw the diagram: the incoming ray makes angle θ\theta with the plane itself.

What Does This Tell Us?

If you know the X-ray wavelength (you do — it's a property of the source, like the KαK_\alpha line from a copper target) and you measure the angle θ\theta at which a strong reflected beam appears, you can calculate dd:

d=nλ2sin⁡θd = \frac{n\lambda}{2\sin\theta}

That dd is the spacing between atomic planes in the crystal. Different sets of planes (different orientations) give different dd values. By measuring all the angles at which diffraction occurs, you can reconstruct the entire three-dimensional arrangement of atoms — the crystal structure.

Note

  • Single crystal: rotate it and record many sharp spots — each spot corresponds to a different set of planes satisfying Bragg's law.
  • Powder sample: millions of tiny crystals oriented randomly. For any given dd, some crystals will be at the right angle. You get cones of diffracted X-rays, which appear as rings on a detector. This is the Debye-Scherrer method.

Why X-Rays? …

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