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Q.Find the mean deviation about the mean for the following data - 3,6,10,4,9,103, 6, 10, 4, 9, 10.

Telangana TsbieTelangana Board of Intermediate Education 2026Subjective· 2mImportance★★★★★
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Mean =7=7; the sum of ∣xi−7∣|x_i-7| is 1616, so mean deviation =166=83=\dfrac{16}{6}=\dfrac{8}{3}.

Data: 3,6,10,4,9,103, 6, 10, 4, 9, 10 with n=6n = 6.

Mean xˉ=3+6+10+4+9+106=426=7\bar{x} = \dfrac{3+6+10+4+9+10}{6} = \dfrac{42}{6} = 7.

Absolute deviations ∣xi−7∣|x_i - 7|: ∣3−7∣=4, ∣6−7∣=1, ∣10−7∣=3, ∣4−7∣=3, ∣9−7∣=2, ∣10−7∣=3|3-7|=4,\ |6-7|=1,\ |10-7|=3,\ |4-7|=3,\ |9-7|=2,\ |10-7|=3.

Sum of absolute deviations =4+1+3+3+2+3=16= 4+1+3+3+2+3 = 16.

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